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An economy is an immensely complicated network of interdependences.
Changes in one part can ripple out to affect other parts.
Economists have struggled to be able to describe, and to make
predictions about, such a complicated object.
Mathematical models using systems of linear equations
have emerged as a key tool.
One is Input-Output Analysis, pioneered by
W. Leontief,
who won the 1973 Nobel Prize in Economics.

Consider an economy with many parts, two of which are the steel industry and
the auto industry.
As they work to meet the demand for their product
from other parts of the economy, that is, from users external to the steel and
auto sectors, these two interact tightly.
For instance, should the external demand for autos go up, that would lead to
an increase in the auto industry's usage of steel.
Or, should the external demand for steel fall, then it would lead to a fall in
steel's purchase of autos.
The type of Input-Output model we will consider takes in the external demands
and then predicts how the two interact to meet those demands.

We start with a listing of production and consumption statistics.
(These numbers, giving dollar values in
millions, are excerpted from
(Leontief 1965), describing the 1958 U.S. economy.
Today's statistics would be quite different, both because of
inflation and because of technical changes in the industries.)

used by       steelused by       autoused by       otherstotal
value of       steel5 3952 66425 448
value of       auto489 03030 346

For instance, the dollar value of steel used by the auto industry in this
year is {}2 , 664 million.
Note that industries may consume some of their own output.

We can fill in the blanks for the external demand.
This year's value of the steel used by others this year is {}17 , 389
and this year's value of the auto used by others is {}21 , 268.
With that, we have a complete description of the external demands and of
how auto and steel interact, this year, to meet them.

Now, imagine that the external demand for steel has recently been going up by
200 per year and so we estimate that next year it will be {}17 , 589.
Imagine also that for similar reasons we estimate that next year's
external demand for autos will be down 25 to {}21 , 243.
We wish to predict next year's total outputs.

That prediction isn't as simple as adding 200 to this year's steel
total and subtracting 25 from this year's auto total.
For one thing, a rise in steel will cause
that industry to have an increased demand for autos, which will mitigate,
to some extent, the loss in external demand for autos.
On the other hand, the drop in external demand for autos will cause
the auto industry to use less steel, and so lessen somewhat the
upswing in steel's business.
In short, these two industries form a system,
and we need to predict the totals at which the system as a whole will settle.

For that prediction, let s be next years total production of steel and
let a be next year's total output of autos.
We form these equations.

\begin{matrix}\text{next year} \text{'} \text{s production of steel} & = \text{next year} \text{'} \text{s use of steel by steel} \\ & \ + \text{next year} \text{'} \text{s use of steel by auto} \\ & \ + \text{next year} \text{'} \text{s use of steel by others} \\ \text{next year} \text{'} \text{s production of autos} & = \text{next year} \text{'} \text{s use of autos by steel} \\ & \ + \text{next year} \text{'} \text{s use of autos by auto} \\ & \ + \text{next year} \text{'} \text{s use of autos by others}\end{matrix}

On the left side of those equations go the unknowns s and a.
At the ends of the right sides go our external demand estimates for next
year {}17 , 589 and {}21 , 243.
For the remaining four terms, we look to the table of this year's information
about how the industries interact.

For instance, for next year's use of steel by steel, we note that this year the
steel industry used 5395 units of steel input to produce {}25 , 448 units of
steel output.
So next year, when the steel industry will produce s units out,
we expect that doing so will take s ⋅ ( 5395 ) / ( 25 \ 448 )
units of steel input— this is simply the assumption that input is
proportional to output.
(We are assuming that the ratio of input to output remains constant over time;
in practice, models may try to take account of trends of change in the
ratios.)

Next year's use of steel by the auto industry is similar.
This year, the auto industry uses 2664 units of steel input to produce
30346 units of auto output.
So next year, when the auto industry's total output is a, we expect it to
consume a ⋅ ( 2664 ) / ( 30346 ) units of steel.

Filling in the other equation in the same way, we get this system of linear
equation.

\begin{matrix}\frac{5 \ 395}{25 \ 448} ⋅ s & + & \frac{2 \ 664}{30 \ 346} ⋅ a & + & 17 \ 589 & = & s \\ \frac{48}{25 \ 448} ⋅ s & + & \frac{9 \ 030}{30 \ 346} ⋅ a & + & 21 \ 243 & = & a\end{matrix}

Gauss' method on this system.

\begin{matrix}( 20 \ 053 / 25 \ 448 ) s & − & ( 2 \ 664 / 30 \ 346 ) a & = & 17 \ 589 \\ − ( 48 / 25 \ 448 ) s & + & ( 21 \ 316 / 30 \ 346 ) a & = & 21 \ 243\end{matrix}

gives s = 25 \ 698 and a = 30 \ 311.

Looking back, recall that above we described why the prediction of next year's
totals isn't as simple as adding 200 to last year's steel total and
subtracting 25 from last year's auto total.
In fact, comparing these totals for next year
to the ones given at the start for the current year
shows that, despite the drop in external demand, the total production of the
auto industry is predicted to rise.
The increase in internal demand for autos caused by steel's sharp rise in
business more than makes up for the loss in external demand for autos.

One of the advantages of having a mathematical model is that we can
ask "What if ...?" questions.
For instance, we can ask
"What if the estimates for next year's external demands are somewhat off?"
To try to understand how much the model's predictions change in
reaction to changes in our estimates, we can try revising our estimate of
next year's external steel demand from {}17 , 589 down to
{}17 , 489, while keeping the assumption of next year's external demand for
autos fixed at {}21 , 243.
The resulting system

\begin{matrix}( 20 \ 053 / 25 \ 448 ) s & − & ( 2 \ 664 / 30 \ 346 ) a & = & 17 \ 489 \\ − ( 48 / 25 \ 448 ) s & + & ( 21 \ 316 / 30 \ 346 ) a & = & 21 \ 243\end{matrix}

when solved gives s = 25 \ 571 and a = 30 \ 311.
This kind of exploration of the model is sensitivity analysis.
We are seeing how sensitive the predictions of our model are to the
accuracy of the assumptions.

Obviously, we can consider larger models that detail the interactions
among more sectors of an economy.
These models are typically solved on a computer, using the techniques
of matrix algebra that we will develop in Chapter Three.
Some examples are given in the exercises.
Obviously also, a single model does not suit every case; expert
judgment is needed to see if the assumptions underlying the model
are reasonable for a particular case.
With those caveats,
however, this model has proven in practice to be a useful and accurate tool for
economic analysis.
For further reading, try (Leontief 1951) and (Leontief 1965).

Exercises

Hint: these systems are easiest to solve on a computer.

Problem 1

With the steel-auto system given above, estimate next year's
total productions in these cases.

  • Next year's external demands are: up 200 from this
    year for steel, and unchanged for autos.
  • Next year's external demands are: up 100 for steel, and

up 200 for autos.

  • Next year's external demands are: up 200 for steel, and
    up 200 for autos.

Problem 2

In the steel-auto system, the ratio for the use of steel by the auto
industry is {}2 \ 664 / 30 \ 346, about 0.0878.
Imagine that a new process for making autos reduces this
ratio to .0500.

  • How will the predictions for next year's total
    productions change compared to the first example discussed
    above (i.e., taking next year's external demands to be
    {}17 , 589 for steel and {}21 , 243 for autos)?
  • Predict next year's totals if, in addition,

the external demand for
autos rises to be {}21 , 500 because the new cars are cheaper.

Problem 3

This table gives the numbers for the auto-steel system from
a different year, 1947 (see Leontief 1951).
The units here are billions of 1947 dollars.

used by       steelused by       autoused by       otherstotal
value of       steel6.901.2818.69
value of       auto04.4014.27
  • Solve for total output if next year's external
    demands are: steel's demand up 10% and auto's demand up
    15%.
  • How do the ratios compare to those given above in the

discussion for the 1958 economy?

  • Solve the 1947 equations with the 1958 external demands
    (note the difference in units; a 1947 dollar buys about
    what $1.30 in 1958 dollars buys).
    How far off are the predictions for total output?

Problem 4

Predict next year's total productions of each of the three
sectors of the hypothetical economy shown below

used by       farmused by       railused by       shippingused by       otherstotal
value of       farm2550100500
value of       rail255050300
value of       shipping15100500

if next year's external demands are as stated.

  • 625 for farm, 200 for rail, 475 for shipping
  • 650 for farm, 150 for rail, 450 for shipping

Problem 5

This table gives the interrelationships among three segments of an
economy (see Clark & Coupe 1967).

used by       foodused by       wholesaleused by       retailused by       otherstotal
value of       food02 3184 67911 869
value of       wholesale3931 08922 459122 242
value of       retail35375116 041

We will do an Input-Output analysis on this
system.

  • Fill in the numbers for this year's external
    demands.
  • Set up the linear system, leaving next year's

external demands blank.

  • Solve the system where next year's external demands
    are calculated by taking this year's external demands and
    inflating them 10%.
    Do all three sectors increase their total business by
    10%?
    Do they all even increase at the same rate?
  • Solve the system where next year's external demands

are calculated by taking this year's external demands and
reducing them 7%.
(The study from which these numbers are taken concluded that
because of the closing of a local military facility, overall
personal income in the area would fall 7%, so this might
be a first guess at what would actually happen.)

Solutions

References

  • Leontief, Wassily W. (1951), "Input-Output Economics", Scientific American, 185 (4): 15 {{citation}}: Unknown parameter |month= ignored (help).
  • Leontief, Wassily W. (1965), "The Structure of the U.S. Economy", Scientific American, 212 (4): 25 {{citation}}: Unknown parameter |month= ignored (help).
  • Clark, David H.; Coupe, John D. (1967), "The Bangor Area Economy Its Present and Future", Reprot to the City of Bangor, ME {{citation}}: Cite has empty unknown parameter: |1= (help); Unknown parameter |month= ignored (help).

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